A container is divided into two chambers by a partition. The volume...

Let common equilibrium pressure of mixture is $P$ atmp. then

$\dfrac{f}{2}{P}_{1}{V}_{1} + \dfrac{f}{2}{P}_{2}{V}_{2} = \dfrac{f}{2}P\left({V}_{1} + {V}_{2}\right)$

$\dfrac{f}{2}\left(2\right)\left(4 . 5\right) + \dfrac{f}{2}\left(3\right)\left(5 . 5\right) = \dfrac{f}{2}P\left(4 . 5 + 5 . 5\right)$

$⇒ P = 2 . 55 = x \times {10}^{- 1}$ atmp

So $x = 25 . 5 \approx 26$ (Nearest integer)