JEE Main20207 Jan 2020Evening ShiftPhysicsThermal Properties of MatterActual
M grams of steam at 100 o C is mixed with 200 g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40 o C [heat of vaporization of water is 540 c a l / g and heat of fusion of ice is 80 c a l / g ], the value of M is ________
Correct answer
0
Step-by-step solution
M i c e L f + M i c e 40 - 0 C w = M s t e a m L v + M s t e a m 100 - 40 C w ⇒ 200 80 + 40 1 = M 540 + 60 1 ⇒ 200 120 = M 600 M = 40   g m