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JEE Main 20207 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Evening Shift
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2020 · 7 January · Evening Shift · Physics · Thermal Properties of Matter

M grams of steam at 100 ^ o C is mixed with 200g of ice at its...

MM grams of steam at 100oC{100}^{o}C is mixed with 200g200g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40oC{40}^{o}C [heat of vaporization of water is 540cal/g540cal / g and heat of fusion of ice is 80cal/g80cal / g ], the value of MM is ________

Correct answer

0

Step-by-step solution

MiceLf+Mice(40−0)Cw=MsteamLv+Msteam(100−40)Cw{M}_{ice}{L}_{f} + {\text{M}}_{ice}\left(40 - 0\right){C}_{w} = {M}_{steam}Lv + {M}_{steam}\left(100 - 40\right){C}_{w}
⇒200[80+40(1)]=M[540+60(1)]⇒ 200\left[80 + 40\left(1\right)\right] = M\left[540 + 60\left(1\right)\right]
⇒200(120)=M(600)⇒ 200\left(120\right) = M\left(600\right)
M=40gmM = 40gm
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