JEE Main201912 Apr 2019Morning ShiftPhysicsThermal Properties of MatterActual
When M 1 gram of ice at - 10 o C (specific heat = 0.5 c a l g - 1 ℃ - 1 ) is added to M 2 gram of water at 50 o C , finally no ice is left and the water is at 0 o C . The value of latent heat of ice, in c a l g - 1 is:
Options
- A50 M 2 M 1
- B5 M 1 M 2 - 50
- C5 M 2 M 1 - 5
- D5 0 M 2 M 1 - 5
Correct answer
D. 5 0 M 2 M 1 - 5
Step-by-step solution
Principle of calorimetry M 1 S i c e 0 - - 10 + M 1 L f = M 2 S w a t e r 50 - 0 M 1 0.5 10 + M 1 L f = M 2 50 5 M 1 + M 1 L f = M 2 50 L f = 50 M 2 M 1 - 5