A heat source at T = 10 ^ 3 K is connected to another heat...

Given,

Temperature of heat source, ${T}_{H} = {10}^{3}K$,

Temperature of heat reservoir, ${T}_{L} = {10}^{2}K$,

Conductivity of copper $K = 0 . 1W{K}^{- 1}{m}^{- 1}$

From the equation of steady-state heat flow,

$\dfrac{d Q}{d t} = \dfrac{KA ∆ T}{L}$

Heat energy flux can be defined as the rate of heat energy transfer through a given surface.

$\dfrac{1}{A}\left(\dfrac{d Q}{d t}\right) = K \times \dfrac{1000 - 100}{1} = 90W{m}^{- 2}$