In an experiment, a sphere of aluminium of mass 0 . 20 kg is heated up to 150 ° C . Immediately, it is put into water of volume 150 cc at 27 o C kept in a calorimeter of water equivalent to 0 . 025 kg . The final temperature of the system is 40 o C . The specific heat of the aluminium is(take 4 . 2 Joule = 1 calorie )

Step-by-step solution

Let S be the specific heat of aluminium Q given = Q used ⇒ 1000 × 0.2 × S × ( 150 − 40 ) = 150 × 1 × ( 40 − 27 ) + 25 × 1 × ( 40 − 27 ) ⇒ 200 × S × 110 = 150 × 13 + 25 × 13 ⇒ S = 13 × 175 200 × 110 = 0.1034   cal   g - 1   ° C ⇒ S = 103.4   × 4.2   J   kg - 1   ° C = 434   J   kg - 1 ° C