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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2014 · 6 April · Physics · Thermal Properties of Matter

The pressure that has to be applied to the ends of a steel wire of...

The pressure that has to be applied to the ends of a steel wire of length 10cm10cm to keep its length constant when its temperature is raised by 100°C100 ° C is :
(For steel, Young's modulus is 2×1011Nm−22 \times {10}^{11}N{m}^{- 2} and coefficient of thermal expansion is 1.1×10−5K−11 . 1 \times {10}^{- 5}{K}^{- 1})

Options

  1. A2.2×108Pa2 .2 \times {10}^{8}Pa
  2. B2.2×109Pa2 .2 \times {10}^{9}Pa
  3. C2.2×107Pa2 .2 \times {10}^{7}Pa
  4. D2.2×106Pa2 .2 \times {10}^{6}Pa

Correct answer

A. 2.2×108Pa2 .2 \times {10}^{8}Pa

Step-by-step solution

Young's modulus, Y=FAL\DeltaLY = \dfrac{F}{A}\dfrac{L}{\DeltaL}

∴FA=Y\DeltaLL=Yα\DeltaT∴ \dfrac{F}{A} = Y\dfrac{\DeltaL}{L} = Y\alpha\DeltaT

∴P=2×1011×1.1×10−5×102∴ P = 2{\times 10}^{11} \times 1 .1 \times {10}^{- 5} \times {10}^{2}

∴P=2.2×108Pa∴ P = 2 . 2 \times {10}^{8}Pa
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