500 ~g of water and 100 ~g of ice at 0^ C are in a calorimeter whose water equivalent is 40 ~g .10 ~g of steam at 100^ C is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal / g , Latent heat of steam =540 cal / g

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500 ~g of water and 100 ~g of ice at 0^ C are in a calorimeter whose water equivalent is 40 ~g .10 ~g of steam at 100^ C is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal / g , Latent heat of steam =540 cal / g )

Quantrex Academy · Accepted Answer

Correct answer: B. 590 ~g

As 1 ~g of steam at 100^ C melts 8 ~g of ice at 0^ C . 10 ~g of steam will melt 8 10 ~g of ice at 0^ C Water in calorimeter =500+80+10 ~g =590 ~g

500 ~g of water and 100 ~g of ice at 0^ C are in a calorimeter whose water equivalent is 40 ~g .10 ~g of steam at 100^ C is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal / g , Latent heat of steam =540 cal / g )

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