JEE Main2013PhysicsThermal Properties of MatterActual
On a linear temperature scale Y , water freezes at -160^ Y and boils at -50^ Y . On this Y scale, a temperature of 340 ~K would be read as : (water freezes at 273 ~K and boils at 373 ~K )
Options
- A-73.7^ Y
- B-233.7^ Y
- C-86.3^ Y
- D-106.3^ Y
Correct answer
C. -86.3^ Y
Step-by-step solution
Reading on any scale - LFP UFP - LFP = constant for all scales 340-273 373-273 = ^ y -(-160) -50-(-160) 67 100 = y +160 110 y=-86.3^ y