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JEE Main 2004

Exam: JEE Main
Year: 2004
Subject: Physics
Chapter: Thermal Properties of Matter

JEE Main 2004 · Physics · Thermal Properties of Matter

The temperature of two outer surfaces of a composite slab,...

The temperature of two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal conductivity

K and

2 K

and thickness

x

and

4 x

, respectively are

T_2

and

T_1\left(T_2>T_1\right)

. The rate of heat transfer through the slab, in a steady state is \left(\frac{A\left(T_2-T_1\right) K}{x}\right) f

, with

f

equal to

The temperature of two outer surfaces of a composite slab, consisting of two materials having coefficients of thermal

Options

A1
B $1 / 2$
C $2 / 3$
D $1 / 3$

Correct answer

D. $1 / 3$

Step-by-step solution

\Delta \mathrm{q}=\frac{\mathrm{kA}}{\mathrm{x}}\left[\mathrm{T}_2-\frac{2 \mathrm{~T}_2-\mathrm{T}_1}{3}\right]

=\frac{\mathrm{kA}}{3 \mathrm{x}}\left[\mathrm{T}_2-\mathrm{T}_1\right]

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