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JEE Main 2004
Exam
JEE Main
Year
2004
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2004 · Physics · Thermal Properties of Matter

Time taken by a 836 ~W heater to heat one litre of water from 10^ C...

Time taken by a 836 W836 \mathrm{~W} heater to heat one litre of water from 10∘C10^{\circ} \mathrm{C} to 40∘C40^{\circ} \mathrm{C} is

Options

  1. A50 s50 \mathrm{~s}
  2. B100 s100 \mathrm{~s}
  3. C150 s150 \mathrm{~s}
  4. D200 s200 \mathrm{~s}

Correct answer

C. 150 s150 \mathrm{~s}

Step-by-step solution

Let t\mathrm{t} be the time taken, then 836×t4.2=1000×1×(40−10)[ using Q=mst]⇒t=150 sec. \begin{aligned}& \frac{836 \times t}{4.2}=1000 \times1 \times(40-10)[\text{ using }Q=m s t] \\ & \Rightarrow t=150 \text{ sec. } \end{aligned}
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