A thermodynamic system is taken through the cyclic process $A B C$ as shown in the figure. The total work done by the system during the cycle $A B C$ is $\_\_\_\_$ J.

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A thermodynamic system is taken through the cyclic process A B C as shown in the figure. The total work done by the system during the cycle A B C is \_\_\_\_ J.

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Correct answer: D. Statement I is false but Statement II is true

From the P-V diagram: A(2,100), B(5,300), C(5,100) in Pa and m³ units.
Process A→B is linear. Equation:

P = 100 + \frac{200}{3}(V-2)

W_{AB} = \int_2^5 \frac{200V - 100}{3} dV = \frac{1}{3}[100V^2 - 100V]_2^5 = \frac{1800}{3} = 600

J
Process B→C is isobaric:

W_{BC} = 300(5-5) = 0

J
Process C→A is isobaric:

W_{CA} = 100(2-5) = -300

J
Total work done by system:

W = 600 + 0 - 300 = 300

J

A thermodynamic system is taken through the cyclic process A B C as...

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