JEE Main202628 January 2026Evening ShiftPhysicsThermodynamicsActual
A thermodynamic system is taken through the cyclic process A B C as shown in the figure. The total work done by the system during the cycle A B C is _ _ _ _ J.
Options
- ABoth Statement I and Statement II are true
- BBoth Statement I and Statement II are false
- CStatement I is true but Statement II is false
- DStatement I is false but Statement II is true
Correct answer
D. Statement I is false but Statement II is true
Step-by-step solution
From the P-V diagram: A(2,100), B(5,300), C(5,100) in Pa and m³ units. Process A→B is linear. Equation: P = 100 + 200 3 (V-2) W_ AB = ₂^5 200V - 100 3 dV = 1 3 [100V^2 - 100V]₂^5 = 1800 3 = 600 J Process B→C is isobaric: W_ BC = 300(5-5) = 0 J Process C→A is isobaric: W_ CA = 100(2-5) = -300 J Total work done by system: W = 600 + 0 - 300 = 300 J