Match List-I with List-II. ( List - I List - II (A) Isobaric (I) Δ Q= Δ W (B) Isochoric (II) Δ Q= Δ U (C) Adiabatic (III) Δ Q= zero (D) Isothermal (IV) Δ Q= Δ U+P Δ V ) Δ Q= Heat supplied Δ W= Work done by the system Δ

Correct answer: C. (A)-(IV), (B)-(II), (C)-(III), (D)-(I) (A) Isobaric ( P=C ) Δ Q=Δ U+P Δ ~V (B) Isochoric ( V=C ) Δ Q=Δ U (C) Adiabatic (Δ Q=0) Δ Q=0 (D) Isothermal (Δ U=0) Δ Q=Δ W

JEE Main 20254 AprilEvening Shift

Exam: JEE Main
Year: 2025
Date: 4 April
Shift: Evening Shift
Subject: Physics
Chapter: Thermodynamics

JEE Main 2025 · 4 April · Evening Shift · Physics · Thermodynamics

Match List-I with List-II. ( List - I List - II (A) Isobaric (I) Δ...

Match List-I with List-II.
(

	List - I		List - II
(A)	Isobaric	(I)	$\Delta$ Q= $\Delta$ W
(B)	Isochoric	(II)	$\Delta$ Q= $\Delta$ U
(C)	Adiabatic	(III)	$\Delta$ Q= zero
(D)	Isothermal	(IV)	$\Delta$ Q= $\Delta$ U+P $\Delta$ V

)

\Delta \mathrm{Q}=

Heat supplied

\Delta \mathrm{W}=

Work done by the system

\Delta \mathrm{U}=

Change in internal energy

\mathrm{P}=

Pressure of the system

\Delta \mathrm{V}=

Change in volume of the system
Choose the correct answer from the options given below:

Options

A(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
B(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
C(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
D(A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Correct answer

C. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)

Step-by-step solution

(A) Isobaric

(

\mathrm{P}=\mathrm{C}

)

\Delta \mathrm{Q}=\Delta \mathrm{U}+\mathrm{P} \Delta \mathrm{~V}

(B) Isochoric

(

\mathrm{V}=\mathrm{C}

)

\Delta \mathrm{Q}=\Delta \mathrm{U}

(\Delta \mathrm{Q}=0)

\Delta \mathrm{Q}=0

(D) Isothermal

(\Delta \mathrm{U}=0)

\Delta \mathrm{Q}=\Delta \mathrm{W}

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