JEE Main202529 Jan 2025Evening ShiftPhysicsThermodynamicsActual
A poly-atomic molecule ( C_V=3 R, C_P=4 R , where R is gas constant) goes from phase space point A ( P _ A =10^5 ~Pa , ~V _ A =4 10⁻⁶ ~m ^3 ) to point B ( P _ B =5 10^4 ~Pa , ~V _ B =6 10⁻⁶ ~m ^3 ) to point C ( P _ C =10^4 . . Pa , V _ C =8 10⁻⁶ ~m ^3 ) . A to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system is :
Options
- A500 R ( 3+ 4)
- B450 R ( 4- 3)
- C500 R 2
- D400 R 4
Correct answer
B. 450 R ( 4- 3)
Step-by-step solution
aligned & Q _ AB =0 adiabatic & Q _ BC = W _ BC & = nRT n ( V _ C V _ B )=450 R n ( 8 10⁻⁶ 6 10⁻⁶ ) & =450 R n ( 4 3 )=450 R ( 4- n 3) & Q = Q _ AB + Q _ BC & Q =450 R ( n 4- n 3) aligned