JEE Main20246 Apr 2024Evening ShiftPhysicsThermodynamicsActual
A total of 48 ~J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2^ C . The work done by the gas is: Given, R =8.3 ~J ~K ⁻¹ ~mol ⁻¹ .
Options
- A24.9 ~J
- B72.9 ~J
- C48 ~J
- D23.1 ~J
Correct answer
D. 23.1 ~J
Step-by-step solution
1^ st law of thermodynamics aligned & Q = U + W & +48= nC _ v T + W & 48=(1) ( 3 R 2 )(2)+ W & W =48-3 R & W =48-3 (8.3) & W =23.1 Joule aligned