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A sample of gas at temperature T is adiabatically expanded to double its volume. Adiabatic constant for the gas is =3 / 2 . The work done by the gas in the process is: ( =1 ~mole )

Options

  1. AR T[1-2 2 ]
  2. BR T[ 2 -2]
  3. CR T[2- 2 ]
  4. DR T[2 2 -1]

Correct answer

C. R T[2- 2 ]

Step-by-step solution

aligned & W = nR T 1- & TV ^ -1 = constan t = T _ f (2 ~V )^ -1 & ~T _ f = T ( 1 2 )^ 1 / 2 = T 2 & ~W = R ( T 2 - T ) 1- 3 2 =2 RT ( 2 -1) 2 & = RT (2- 2 ) aligned

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