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JEE Main 20241 FebruaryEvening Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Evening Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2024 · 1 February · Evening Shift · Physics · Thermodynamics

A diatomic gas ( γ = 1 . 4 ) does 200J of work when it is expanded...

A diatomic gas (γ=1.4)( \gamma = 1 . 4 ) does 200J200J of work when it is expanded isobarically. The heat given to the gas in the process is :

Options

  1. A850J850J
  2. B800J800J
  3. C600J600J
  4. D700J700J

Correct answer

D. 700J700J

Step-by-step solution

For degree of freedom, we can write

γ=1+2f=1.4⇒2f=0.4\gamma = 1 + \dfrac{2}{f} = 1 . 4 ⇒ \dfrac{2}{f} = 0 . 4

⇒f=5⇒ f = 5

For isobaric process, W=nR\DeltaT=200JW = nR\DeltaT = 200J.

Now, we can write

Q=(f+22)nRΔTQ = \left(\dfrac{f + 2}{2}\right)nR \Delta T

=72×200=700J= \dfrac{7}{2} \times 200 = 700J

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