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The given figure represents two isobaric processes for the same mass of an ideal gas, then

Options

  1. AP 2 ≥ P 1
  2. BP 2 > P 1
  3. CP 1 = P 2
  4. DP 1 > P 2

Correct answer

D. P 1 > P 2

Step-by-step solution

As we know, P V = n R T ⇒ V = n R P T Therefore, slope = n R P Or slope ∝ 1 P As Slope 2 > Slope 1 ⇒ P 2 < P 1

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