0 . 08kg air is heated at constant volume through 5 ° C . The...

The amount of work done for the given process should be zero, as the process is an isochoric process.

Thus, the change in internal energy will be equal to the heat exchanged in the process. Mathematically,

$Q = ∆ U$

Now,

$∆ U = ms ∆ T . . . \left(1\right)$

From equation (1), it follows that

$\begin{cases}∆ U & = & 0 . 08 \times ( 170 \times 4 . 18 ) \times 5J \\ & \approx & 284J\end{cases}$