JEE Main 202312 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 12 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Thermodynamics
JEE Main 2023 · 12 April · Morning Shift · Physics · Thermodynamics
An engine operating between the boiling and freezing points of...
An engine operating between the boiling and freezing points of water will have
A. Efficiency more than .
B. Efficiency less than the efficiency of a Carnot engine operating between the same two temperatures.
C. Efficiency equal to .
D. Efficiency less than .
Choose the correct answer from the options given below
Options
- AB, C and D only
- BA and B only
- CB and D only
- DB and C only
Correct answer
C. B and D only
Step-by-step solution
The efficiency of Carnot engine can be calculated as follows:
\begin{cases}{η}_{C} & = & \left(1 - \dfrac{273}{373}\right) \times 100 % \\ & = & 26 . 8 %\end{cases}
Hence, the efficiency of the engine is given by
.