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JEE Main20238 Apr 2023Evening ShiftPhysicsThermodynamicsActual

Work done by a Carnot engine operating between temperatures 127 ° C and 27 ° C is 2 kJ . The amount of heat transferred to the engine by the reservoir is:

Options

  1. A8   kJ
  2. B2 . 67   kJ
  3. C2   kJ
  4. D4   kJ

Correct answer

A. 8   kJ

Step-by-step solution

The temperatures in Kelvin scales are T 2 = 27   ° C + 273 = 300   K T 1 = 127   ° C + 273 = 400   K The efficiency of the Carnot engine is η = 1 - T 2 T 1 = 1 - 300 400 = 1 4 Using the relation, η = W Q ⇒ 2   kJ Q = 1 4 ⇒ Q = 8   kJ

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