The pressure of a gas changes linearly with volume from A to B as shown in figure. If no heat is supplied to or extracted from the gas then change in the internal energy of the gas will be

Step-by-step solution

Given here, ∆ Q = 0 From first law of thermodynamics, ∆ Q = ∆ U + W , where, ∆ U is change in internal energy and W is work done. We have, ∆ U = - W W = Area   under   P - V   curve = ∫ P d V Here, volume decreases, hence work done by system will be negative. ∆ U = - W = 30 × 10 3 × 150 × 10 - 6 = 4500 × 10 - 3 = 4 . 5   J