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JEE Main202324 Jan 2023Evening ShiftPhysicsThermodynamicsActual

Let γ 1 be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and γ 2 be the similar ratio of diatomic gas. Considering the diatomic gas molecule as a rigid rotator, the ratio γ 1 γ 2 is:

Options

  1. A27 35
  2. B35 27
  3. C25 21
  4. D21 25

Correct answer

C. 25 21

Step-by-step solution

As we know, C v = f R 2 and C p = C v + R = f R 2 + R Therefore, γ = C p C v = 1 + 2 f For monatomic gas, f = 3 and hence γ 1 = 5 3 For diatomic gas, f = 5 and hence γ 2 = 7 5 Required ratio, γ 1 γ 2 = 25 21

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