At a certain temperature, the degrees of freedom per molecule for...

For constant pressure process,

Work done is given by $W = nR\DeltaT = 150J$, here, $R$ is gas constant.

Now, for above process, $f = 8$.

So, specific heat at constant pressure is ${C}_{P} = \left(1 + \dfrac{f}{2}\right)R$.

Amount of heat adsorbed by the gas is

$Q = n{C}_{P}R\DeltaT = \left(\dfrac{f}{2} + 1\right)nR\DeltaT = \left(\dfrac{8}{2} + 1\right)150 = 750J$