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The width of one of the two slits in a Young's double slit experiment is three times the other slit. If the amplitude of the light coming from a slit is proportional to the slit-width, the ratio of minimum to maximum intensity in the interference pattern is x : 4 where x is _ _ _ _ _ _ _ .

Correct answer

1

Step-by-step solution

Given amplitude slit width Also intensity ( Amplitude )^2 ( Slit width )^2 I₁ I₂ = ( 3 1 )^2=9 I₁=9 I₂ I_ I_ = ( I₁ - I₂ I₁ + I₂ )^2= ( 3-1 3+1 )^2= 1 4 = x 4 x=1

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