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JEE Main 202116 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Evening Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2021 · 16 March · Evening Shift · Physics · Thermodynamics

For an ideal heat engine, the temperature of the source is 127 ° C...

For an ideal heat engine, the temperature of the source is 127°C127 ° C. In order to have 6060 % efficiency the temperature of the sink should be __________C∘C ∘. (Round off to the nearest integer)

Correct answer

0

Step-by-step solution

n=0.60=1−TLTHn = 0 . 60 = 1 - \dfrac{{T}_{L}}{{T}_{H}}

TLTH=0.4⇒TL=0.4×400\dfrac{{T}_{L}}{{T}_{H}} = 0 . 4 ⇒ {T}_{L} = 0 . 4 \times 400

=160K= 160K

=−113°C= - 113 ° C

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