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JEE Main 20206 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Evening Shift
Subject
Physics
Chapter
Thermodynamics

JEE Main 2020 · 6 September · Evening Shift · Physics · Thermodynamics

An engine operates by taking a monatomic ideal gas through the...

An engine operates by taking a monatomic ideal gas through the cycle shown in the figure. The percentage efficiency of the engine is close to

An engine operates by taking a monatomic ideal gas through the cycle shown in the figure. The percentage efficiency of

Correct answer

19

Step-by-step solution

An engine operates by taking a monatomic ideal gas through the cycle shown in the figure. The percentage efficiency of

W=2P0v0W = 2{P}_{0}{v}_{0}

Q+=WAB+WBC{Q}_{+} = {W}_{AB} + {W}_{BC}

=n.cvΔTAB+nCPΔTBC= n . {c}_{v}{\Delta T}_{AB} + {nC}_{P}{\Delta T}_{B}C

=32×[3P0v0−P0v0]+52[6P0V0−3P0V0]= \dfrac{3}{2} \times \left[3{P}_{0}{v}_{0} - {P}_{0}{v}_{0}\right] + \dfrac{5}{2}\left[6{P}_{0}{V}_{0} - 3{P}_{0}{V}_{0}\right]

=3P0V0+152P0V0= 3{P}_{0}{V}_{0} + \dfrac{15}{2}{P}_{0}{V}_{0}

=212P0V0= \dfrac{21}{2}{P}_{0}{V}_{0}

η=WQ+=2P0V0212P0V0=421η = \dfrac{W}{{Q}_{+}} = \dfrac{2{P}_{0}{V}_{0}}{\dfrac{21}{2}{P}_{0}{V}_{0}} = \dfrac{4}{21}

ηη % = \dfrac{400}{21} \approx 19

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