Match the thermodynamics processes taking place in a system with the correct conditions. In the table : ∆ Q is the heat supplied, ∆ W is the work done and ∆ U is change in internal energy of the system. Process

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Correct answer: D. (I) - (B), (II) - (D), (III) - (A), (IV) - (C)

In Adiabatic& Δ Q = 0, i . e . , ~Exchange of heat does not take place. In Isothermal& Δ U = 0, i . e . , ~Temperature does not change therefore internal energy also remains constant. In Isochoric& Δ W = 0, i . e . , ~Volume remains constant therefore work done is zero. In Isobaric& ∆ U ≠ 0, ∆ W ≠ 0, ∆ Q ≠ 0 W = P . ∆ V , Volume changes so work done is not equal to zero. ∆ U = (f)/(2)P ∆ V , Volume changes therefore internal energy changes. ~ ∆ Q = n C _ p ∆ T , Temperature changes therefore heat also changes. & &

Match the thermodynamics processes taking place in a system with...

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	Process		Condition
(I)	Adiabatic	(A)	$∆ W = 0$
(II)	Isothermal	(B)	$∆ Q = 0$
(III)	Isochoric	(C)	$∆ U \ne 0, ∆ W \ne 0, ∆ Q \ne 0$
(IV)	Isobaric	(D)	$∆ U = 0$