A Carnot engine having an efficiency of 1 10 is being used as a refrigerator. If the work done on the refrigerator is 10 J , the amount of heat absorbed from the reservoir at a lower temperature is

Step-by-step solution

For Carnot engine using as refrigerator W = Q 2 T 1 T 2 - 1 It is given η = 1 10 ⇒ η = 1 - T 2 T 1 ⇒ T 2 T 1 = 9 10 So , Q 2 = 90   J   a s   W = 10   J