A sample of an ideal gas is taken through the cyclic process $abca$ as shown in the figure. The change in the internal energy of the gas along the path $ca$ is $- 180J .$ The gas absorbs $250J$ of heat along the path $ab$ and $60J$ along the path $bc$ . The work done by the gas along the path $abc$ is:

Question

A sample of an ideal gas is taken through the cyclic process

abca

as shown in the figure. The change in the internal energy of the gas along the path

ca

is

- 180J .

The gas absorbs

250J

of heat along the path

ab

and

60J

along the path

bc

. The work done by the gas along the path

abc

is:

A sample of an ideal gas is taken through the cyclic process abca as shown in the figure. The change in the internal

Quantrex Academy · Accepted Answer

Correct answer: A. 130J

In a cyclic process, = 0 From 1st law of thermodynamics Q = + W Q = W Q _ ab + Q _ bc + Q _ ca = W _ abc + W _ ca W _ abc = Q _ ab + Q _ bc + Q _ ca - W _ ca W _ abc = Q _ ab + Q _ bc + U _ ca W _ abc = 250 + 60 - 180 = 130J

A sample of an ideal gas is taken through the cyclic process abca...

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