JEE Main2018PhysicsThermodynamicsActual
One mole of an ideal monatomic gas is taken along the path A B C A as shown in the P V diagram. The maximum temperature attained by the gas along the path B C is given by:
Options
- A25 4 P 0 V 0 R
- B5 8 P 0 V 0 R
- C25 8 P 0 V 0 R
- D25 16 P 0 V 0 R
Correct answer
C. 25 8 P 0 V 0 R
Step-by-step solution
Equation of the line B C , P = P 0 - 2 P 0 V 0 ( V - 2 V 0 ) , the temperature =   P 0 V -   2 P 0 V 2 V 0 + 4 P 0 V 1   × R ⇒ T = P 0 R 5 V - 2 V 2 V 0 ⇒ d T d V = 0 ⇒ 5 - 4 V V 0 = 0 ⇒ V = 5 4 V 0 ⇒ T = P 0 R 5 × 5 V 0 4 - 2 V 0 × 25 16 V 0 2 ⇒ T = 25 8 P 0 V 0 R .