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A Carnot's engine works like a refrigerator between 250 K and 300 K . It receives 500 cal heat from the reservoir at a lower temperature. The amount of work done in each cycle to operate the refrigerator is,

Options

  1. A772   J
  2. B420   J
  3. C2100   J
  4. D2520   J

Correct answer

B. 420   J

Step-by-step solution

η = 1 − T 2 T 1 , efficiency = 1 - T 2 T 1 = W Q 2 + W ⇒ 1 - 250 300 = W Q 2 + W = 420   J

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