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n moles of an ideal gas undergoes a process A → B as shown in the figure. The maximum temperature of the gas during the process will be:

Options

  1. A9 P 0 V 0 2 n R
  2. B9 P 0 V 0 n R
  3. C9 P 0 V 0 4 n R
  4. D3 P 0 V 0 2 n R

Correct answer

C. 9 P 0 V 0 4 n R

Step-by-step solution

Temperature T will be maximum where product of P V is max equation of line P = − P 0 V 0 V + 3 P 0 Multiplying both sides by V , P V = − P 0 V 0 V 2 + 3 P 0 V For maxima, d ( P V ) d V = 0 ⇒                             − 2 P 0 V 0 V + 3 P 0 = 0           ⇒     V = 3 V 0 2 and   P = 3 P 0 2 ⇒       T = P V n R = 9 P 0 V 0 4 n R Altern

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