JEE Main2014PhysicsThermodynamicsActual
During an adiabatic compression, 830 ~J of work is done on 2 moles of a diatomic ideal gas to reduce its volume by 50 % . The change in its temperature is nearly: ( R =8.3 JK ⁻¹ ~mol ⁻¹ )
Options
- A40 ~K
- B33 ~K
- C20 ~K
- D14 ~K
Correct answer
C. 20 ~K
Step-by-step solution
Given : work done, W=830 ~J No. of moles of gas, =2 For diatomic gas =1.4 Work done during an adiabatic change aligned &W= R (T₁-T₂ ) -1 & 830= 2 8.3( T) 1.4-1 = 2 8.3( T) 0.4 & T= 830 0.4 2 8.3 =20 ~K aligned