JEE Main2012PhysicsThermodynamicsActual
n moles of an ideal gas undergo a process A B as shown in the figure. Maximum temperature of the gas during the process is
Options
- A9 P₀ V₀ n R
- B3 P₀ V₀ 2 n R
- C9 P₀ V₀ 2 n R
- D9 P₀ V₀ 4 n R
Correct answer
D. 9 P₀ V₀ 4 n R
Step-by-step solution
For given graph, equation of P - V line is P-2 P₀= 2 P₀-P₀ V₀-2 V₀ (V-V₀ ) So, P=3 P₀- P₀ V₀ V as P V=n R T (3 P₀- P₀ V₀ V ) V=n R T ; For maximum temperature d T d V =0 d T d V =3 P₀- 2 P₀ V₀ V=0 V= 3 2 V₀ Also P= 3 2 P₀ So, T= P V n R = 1 n R 3 2 P₀ 3 2 V₀= 9 P₀ V₀ 4 n R