JEE Main2012PhysicsThermodynamicsActual
A perfect gas at 27^ C is heated at constant pressure so as to double its volume. The final temperature of the gas will be, close to
Options
- A327^ C
- B200^ C
- C54^ C
- D300^ C
Correct answer
A. 327^ C
Step-by-step solution
Given, V₁=V aligned & V₂=2 V & T₁=27^ +273=300 ~K & T₂=? aligned From charle's law V₁ T₁ = V₂ T₂ ( Pressure is constant ) or, V 300 = 2 V T₂ T₂=600 ~K =600-273=327^ C