JEE Main2011PhysicsThermodynamicsActual
A Carnot engine operating between temperatures T₁ and T₂ has efficiency 1 6 . When T₂ is lowered by 62 K , its efficiency increases to 1 3 . Then T₁ and T₂ are, respectively :
Options
- A372 ~K and 330 ~K
- B330 ~K and 268 ~K
- C310 ~K and 248 ~K
- D372 ~K and 310 ~K
Correct answer
D. 372 ~K and 310 ~K
Step-by-step solution
₁= T₁-T₂ T₁ = 1 6 ₂= T₁- (T₂-62 ) T₁ = 1 3 T₁-T₂ T₁ + 62 T₁ = 1 3 1 6 + 62 T₁ = 1 3 62 T₁ = 1 6 T₁=62 6=372 ~K T₁-T₂ T₁ = 1 6 1- T₂ T₁ = 1 6 T₂ 372 = 5 6 T₂=310 ~K