JEE Main2003PhysicsThermodynamicsActual
A Carnot engine takes 3 10^6 cal . of heat from a reservoir at 627^ C , and gives it to a sink at 27^ C . The work done by the engine is
Options
- A4.2 10^6 ~J
- B8.4 10^6 ~J
- C16.8 10^6 ~J
- DZero
Correct answer
B. 8.4 10^6 ~J
Step-by-step solution
= (627+273)-(273+27) 627+273 = 900-300 900 = 600 900 = 2 3 work =( ) Heat = 2 3 3 10^6 4.2 ~J =8.4 10^6 ~J