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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Chemistry
Chapter
Chemical Equilibrium

JIPMER 2015 · Chemistry · Chemical Equilibrium

aligned & If Ag^ + +2 NH_3 leftharpoons Ag(NH_3)_2^ + ; K_1=1.7 ×...

 If Ag++2NH3⇌Ag(NH3)2+;K1=1.7×107Ag++Cl−⇌AgCl;K2=5.4×109\begin{aligned} & \text{ If } \mathrm{Ag}^{+}+2 \mathrm{NH}_3 \rightleftharpoons \mathrm{Ag}\left(\mathrm{NH}_3\right)_2^{+} ; K_1=1.7 \times 10^7 \\ & \mathrm{Ag}^{+}+\mathrm{Cl}^{-} \rightleftharpoons \mathrm{AgCl} ; K_2=5.4 \times 10^9\end{aligned} Then, for AgCl+2NH3⇌[Ag(NH3)2]++Cl−equilibriumconstantwillbe\mathrm{AgCl}+2 \mathrm{NH}_3 \rightleftharpoons\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}+\mathrm{Cl}^{-} equilibrium constant will be

Options

  1. A4.68×10−34.68 \times 10^{-3}
  2. B5.2×10−175.2 \times 10^{-17}
  3. C0.31×10−20.31 \times 10^{-2}
  4. D3.1×10−23.1 \times 10^{-2}

Correct answer

C. 0.31×10−20.31 \times 10^{-2}

Step-by-step solution

For the given reaction, Ag++2NH3⇌Ag(NH3)2+;K1=1.7×107Ag++Cl−⇌AgCl;K2=5.4×109\begin{aligned} \mathrm{Ag}^{+}+2 \mathrm{NH}_3 \rightleftharpoons \mathrm{Ag}\left(\mathrm{NH}_3\right)_2^{+} ; K_1=1.7 \times 10^7 \\ \mathrm{Ag}^{+}+\mathrm{Cl}^{-} \rightleftharpoons \mathrm{AgCl} ; K_2=5.4 \times 10^9\end{aligned} Hence for AgCl⇌Ag++Cl−K2′=1K2=15.4×109\begin{aligned} & \mathrm{AgCl} \rightleftharpoons \mathrm{Ag}^{+}+\mathrm{Cl}^{-} \\ & K_2^{\prime}=\frac{1}{K_2}=\frac{1}{5.4 \times 10^9}\end{aligned} Now for the reaction, AgCl+2NH3⇌[Ag(NH3)2]++Cl−\mathrm{AgCl}+2 \mathrm{NH}_3 \rightleftharpoons\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}+\mathrm{Cl}^{-}K=K1×K2′=1.7×107×15.4×109=0.31×10−2\begin{aligned} K=K_1 \times K_2^{\prime} & =1.7 \times 10^7 \times \frac{1}{5.4 \times 10^9} \\ & =0.31 \times 10^{-2}\end{aligned}$$
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