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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Chemistry
Chapter
Chemical Equilibrium

JIPMER 2016 · Chemistry · Chemical Equilibrium

Both Mg and Fe metal can reduce copper from a solution having Cu^...

Both Mg and Fe metal can reduce copper from a solution having Cu2+\mathrm{Cu}^{2+} ion, according to equilibria. Mg(s)+Cu2+⇌Mg2++Cu(s);K1=6×1090Fe(s)+Cu2+⇌Fe2++Cu(s);K2=3×1026\begin{aligned} & \mathrm{Mg}_{(s)}+\mathrm{Cu}^{2+} \rightleftharpoons \mathrm{Mg}^{2+}+\mathrm{Cu}_{(s)} ; K_1=6 \times 10^{90} \\ & \mathrm{Fe}_{(s)}+\mathrm{Cu}^{2+} \rightleftharpoons \mathrm{Fe}^{2+}+\mathrm{Cu}_{(s)} ; K_2=3 \times 10^{26}\end{aligned} Choose the correct option regarding above equilibrium

Options

  1. AMg removes more Cu2+\mathrm{Cu}^{2+} from solution
  2. BFe removes more Cu2+\mathrm{Cu}^{2+} from solution
  3. CBoth will equally remove Cu2+\mathrm{Cu}^{2+} from solution
  4. DBoth metals cannot remove Cu2+\mathrm{Cu}^{2+} from solution

Correct answer

A. Mg removes more Cu2+\mathrm{Cu}^{2+} from solution

Step-by-step solution

Since, K1>K2K_1 \gt K_2, the product in the first reaction is much more favoured than in the second one. Mg thus removes more Cu2+\mathrm{Cu}^{2+} from solution than Fe does.
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