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JIPMER 2009
Exam
JIPMER
Year
2009
Subject
Chemistry
Chapter
Chemical Equilibrium

JIPMER 2009 · Chemistry · Chemical Equilibrium

9.2 ~g ~N_2 O_4 is heated in a 1 L vessel till equilibrium state is...

9.2 g N2O49.2 \mathrm{~g} \mathrm{~N}_2 \mathrm{O}_4 is heated in a 1 L vessel till equilibrium state is established N2O4(g)⇌2NO2(g)\mathrm{N}_2 \mathrm{O}_4(g) \rightleftharpoons 2 \mathrm{NO}_2(g) In equilibrium state 50% N2O450 \% \mathrm{~N}_2 \mathrm{O}_4 was dissociated, equilibrium constant will be (mol. wt. of N2O4=92\mathrm{N}_2 \mathrm{O}_4=92 )

Options

  1. A0.1
  2. B0.4
  3. C0.3
  4. D0.2

Correct answer

D. 0.2

Step-by-step solution

N2O4( g)⇌2NO2( g)\mathrm{N}_2 \mathrm{O}_4(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2(\mathrm{~g}) Molar concentration of [N2O4]=9.292=0.1 mol/L\left[\mathrm{N}_2 \mathrm{O}_4\right]=\frac{9.2}{92}=0.1 \mathrm{~mol} / \mathrm{L} In equilibrium state when it 50\% dissociates, [N2O4]=0.05M[NO2]=0.1MKc=[NO2]2[ N2O4]=0.1×0.10.05=0.2\begin{aligned} {\left[\mathrm{N}_2 \mathrm{O}_4\right] } & =0.05 \mathrm{M} \\ {\left[\mathrm{NO}_2\right] } & =0.1 \mathrm{M} \\ K_c & =\frac{\left[\mathrm{NO}_2\right]^2}{\left[\mathrm{~N}_2 \mathrm{O}_4\right]} \\ & =\frac{0.1 \times 0.1}{0.05}=0.2 \end{aligned}
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