The product of electrolysis of aqueous NaCl solution on anode and cathode respectively is

Step-by-step solution

In case of electrolysis of aqueous NaCl , oxidation and reduction reaction occurs at anode and cathode respectively as shown below: At cathode H ₂ O ( l )+ e ⁻ 1 2 H ₂( ~g )+ OH ⁻( aq ) At anode Cl ⁻( aq ) 1 2 Cl ₂( ~g )+ e ⁻ Net cell reaction is as follows NaCl ( aq )+ H ₂ O ( l ) Na ⁺( aq )+ OH ⁻( aq )+ 1 2 H ₂( ~g )+ 1 2 Cl ₂( ~g ) Thus, the product of electrolysis of NaCl solution on cathode and anode is H ₂ and Cl ₂ .