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JIPMER 2006
Exam
JIPMER
Year
2006
Subject
Chemistry
Chapter
Electrochemistry

JIPMER 2006 · Chemistry · Electrochemistry

What amount of Cl_2 gas liberated at anode, if 1 ampere current is...

What amount of Cl2\mathrm{Cl}_2 gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution?

Options

  1. A0.66 mol
  2. B0.33 mol
  3. C0.66 g
  4. D0.33 g

Correct answer

C. 0.66 g

Step-by-step solution

2Cl−→Cl21 mole +2e−(At anode) 2×96500 coulomb 2 \mathrm{Cl}^{-} \rightarrow \underset{1 \text{ mole }}{\mathrm{Cl}_2}+\underset{2 \times 96500 \text{ coulomb }}{2 e^{-} \text{(At anode) }}Q=it=1×30×60=1800 coulomb \begin{aligned} Q & =i t=1 \times 30 \times 60 \\ & =1800 \text{ coulomb }\end{aligned}$Theamountofchlorineliberatedbypassing1800coulombofelectriccharge=The amount of chlorine liberated by passing 1800 coulomb of electric charge =\frac{1 \times 1800 \times 71}{2 \times 96500}=0.660.66\mathrm{ g}$
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