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JIPMER2006ChemistryElectrochemistry

What amount of Cl ₂ gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution?

Options

  1. A0.66 mol
  2. B0.33 mol
  3. C0.66 g
  4. D0.33 g

Correct answer

C. 0.66 g

Step-by-step solution

2 Cl ⁻ 1 mole Cl ₂ + 2 96500 coulomb 2 e⁻ (At anode) aligned Q & =i t=1 30 60 & =1800 coulomb aligned The amount of chlorine liberated by passing 1800 coulomb of electric charge = 1 1800 71 2 96500 =0.66 ~g

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