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JIPMER 2005
Exam
JIPMER
Year
2005
Subject
Chemistry
Chapter
Electrochemistry

JIPMER 2005 · Chemistry · Electrochemistry

How much chlorine will be liberated on passing one ampere current...

How much chlorine will be liberated on passing one ampere current for 30 min through NaCl solution?

Options

  1. A0.66 mole
  2. B0.33 mole
  3. C0.66 g
  4. D0.33 g

Correct answer

C. 0.66 g

Step-by-step solution

According to Faraday's law wE=it96500 or w35.5=1×30×6096500⇒=0.662g\begin{aligned} & \frac{w}{E}=\frac{i t}{96500} \\ & \text{ or } \quad \frac{w}{35.5}=\frac{1 \times 30 \times 60}{96500} \\ & \Rightarrow \quad=0.662 \mathrm{ g} \\ & \end{aligned} so, 0.662 g chlorine is liberated.
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