At 25^ C , the dissociation constant of a base, BOH , is 1.0 10⁻¹² . The concentration of hydroxyl ions in 0.01 M aqueous solution of the base would be

Step-by-step solution

Base B O H is dissociated as follows BOH B ⁺+ OH ⁻ So, the dissociation constant of B O H base K_b= [B⁺ ] [ OH ⁻ ] [B OH ] ...(i) At equilibrium [B⁺ ]= [ OH ⁻ ] K_b= [ OH ⁻ ]^2 [B OH ] Given that K_b=1.0 10⁻¹² and BOH = 0.01 ~M aligned Therefore, [ OH ⁻ ]^2 & =1 10⁻¹⁴ [ OH ⁻ ] & =1.0 10⁻⁷ ~mol ~L ⁻¹ aligned