JIPMER2016Chemistryp Block Elements (Group 13 & 14)
In the reaction X+ I ₂+2 HCl SnCl ₄+2 HI The correct option regarding X is/are
Options
- AIt is an strong reducing agent
- BIt is an angular molecule
- CIt is used as a reagent in test of Hg ²⁺ radical
- DAll of the above
Correct answer
D. All of the above
Step-by-step solution
SnCl ₂+ I ₂+2 HCl SnCl ₄+2 HI SnCl ₂ is an strong reducing agent because it is readily oxidised into Sn ⁴⁺ ion. Since, Sn-atom in SnCl ₂ is sp ^2 -hybridised. So, it is an angular molecule. On the other hand, it is used as a reagent in test of Hg ²⁺ radical.