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JIPMER 2010
Exam
JIPMER
Year
2010
Subject
Chemistry
Chapter
Solid State

JIPMER 2010 · Chemistry · Solid State

A solid A B has the NaCl structure. If radius of cation A^ + is 120...

A solid ABA B has the NaCl structure. If radius of cation A+A^{+}is 120 pm , the maximum possible value of the radius of the anion B−B^{-}is

Options

  1. A240 pm
  2. B60 pm
  3. C49.6 pm
  4. D290 pm

Correct answer

D. 290 pm

Step-by-step solution

For NaCl crystal, Radius of cation/radius of anion =0.414=0.414rA+rB−=0.414rB−=rA+0.414=1200.414=290pm\begin{aligned} & \frac{r_{A^{+}}}{r_{B^{-}}}=0.414 \\ & r_{B^{-}}=\frac{r_{A^{+}}}{0.414}=\frac{120}{0.414} \\ & =290 \mathrm{pm} \\ & \end{aligned}$$
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