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JIPMER 2013
Exam
JIPMER
Year
2013
Subject
Chemistry
Chapter
Solutions

JIPMER 2013 · Chemistry · Solutions

The osmotic pressure of blood is 8.21 atm at 37^ C . How much...

The osmotic pressure of blood is 8.21 atm at 37∘C37^{\circ} \mathrm{C}. How much glucose would be used for an injection that is at the same osmotic pressure as blood?

Options

  1. A22.17gL−122.17 \mathrm{gL}^{-1}
  2. B58.14gL−158.14 \mathrm{gL}^{-1}
  3. C61.26gL−161.26 \mathrm{gL}^{-1}
  4. D75.43gL−175.43 \mathrm{gL}^{-1}

Correct answer

B. 58.14gL−158.14 \mathrm{gL}^{-1}

Step-by-step solution

π=CRT or C=πRT=8.21atm/0.0821LatmK−1mol−1×310K=0.323M=0.323×180gL−1=58.14gL−1\begin{aligned} \pi & =C R T \text{ or } C=\frac{\pi}{R T} \\ & =8.21 \mathrm{ atm} / 0.0821 \mathrm{ L} \mathrm{ atm} \mathrm{ K}^{-1} \mathrm{ mol}^{-1} \times 310 \mathrm{ K} \\ & =0.323 \mathrm{M}=0.323 \times 180 \mathrm{gL}^{-1} \\ & =58.14 \mathrm{gL}^{-1}\end{aligned}
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