AIIMS2013ChemistrySolutions
Boiling point of benzene is 353.23 ~K . When 1.8 ~g of non-volatile solute is dissolved in 90 ~g of benzene. Then boiling point is raised to 354.11 ~K . Given K_b (benzene) =2.53 ~kg ~mol ⁻¹ . The molecular mass of non-volatile substance is
Options
- A58 ~g ~mol ⁻¹
- B120 ~g ~mol ⁻¹
- C116 ~g ~mol ⁻¹
- D60 ~g ~mol ⁻¹
Correct answer
A. 58 ~g ~mol ⁻¹
Step-by-step solution
T_b^ =353.23 ~K , W_B=1.8 ~g , W_A=90 ~g _ T_b=354.11 ~K , K_b=2.53 ~kg mol ^ - 1 T_b=T_b-T_b ^ =354.11-353.23=0.88 ~K M_B= W_B K_b 1000 T_b W_A = 1.8 2.53 1000 0.88 90 =57.5 58 ~g ~mol ⁻¹