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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Chemistry
Chapter
States of Matter

JIPMER 2016 · Chemistry · States of Matter

Temperature of a gas is t ~K . What would be the temperature at...

Temperature of a gas is t Kt \mathrm{~K}. What would be the temperature at which volume and pressure, both will reduced to half of the initial values?

Options

  1. At/2
  2. Bt/4
  3. Ct/3
  4. Dt/8

Correct answer

B. t/4

Step-by-step solution

Given that, p1=p,T1=t,V1=vp2=p/2,V2=v/2,T2=?\begin{aligned} & p_1=p, T_1=t, V_1=v \\ & p_2=p / 2, V_2=v / 2, T_2=?\end{aligned} By using p1V1T1=p2V2T2p×Vt=p×V2×2×T2⇒T2=t/4\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2} \frac{p \times V}{t}=\frac{p \times V}{2 \times 2 \times T_2} \Rightarrow T_2=t / 4
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