NEET 2016
- Exam
- NEET
- Year
- 2016
- Subject
- Chemistry
- Chapter
- States of Matter
NEET 2016 · Chemistry · States of Matter
Equal moles of hydrogen and oxygen gases are placed in a container...
Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escape in the time required for one-half of the hydrogen to escape?
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
\dfrac{\dfrac{{n}_{1}}{{t}_{1}}}{\dfrac{{n}_{2}}{{t}_{2}}} = \sqrt{\dfrac{{M}_{2}}{{M}_{1}}} ⇒ {n}_{2} = \dfrac{1}{2}, {n}_{1} = {n}^{′}
⇒ \dfrac{2{t}_{2}{n}^{′}}{{t}_{1}{x}_{1}} = \sqrt{\dfrac{{M}_{2}}{{M}_{1}}} = \sqrt{\dfrac{2}{32}} = \sqrt{\dfrac{1}{16}} = \dfrac{1}{4}
Assuming
\dfrac{2{n}^{′}{t}_{2}}{{t}_{1}} = \dfrac{1}{4}
∴ {n}^{′} = \dfrac{1}{8}
⇒ \dfrac{2{t}_{2}{n}^{′}}{{t}_{1}{x}_{1}} = \sqrt{\dfrac{{M}_{2}}{{M}_{1}}} = \sqrt{\dfrac{2}{32}} = \sqrt{\dfrac{1}{16}} = \dfrac{1}{4}
Assuming
\dfrac{2{n}^{′}{t}_{2}}{{t}_{1}} = \dfrac{1}{4}
∴ {n}^{′} = \dfrac{1}{8}